Question

A cubiod has total surface area of 50 $m^2$ and lateral surface area is 30 $m^2$. Find the area of its base.

Answer 1

Total surface area of cubiod = 50 $m^2$
Lateral surface area = 30 $m^2$
$\therefore$ Area of floor and ceiling = 50-30 = 20 $m^2$
But area of floor = area of ceiling
$\therefore$ Area of base (floor) = $\frac{20}{2}=10m^2$