Question

A cuboid has total surface area of 50 m² and lateral surface area is 30 m². Find the area of its base.

Answer 1

Total surface area of cuboid = 50 m²

Lateral surface area of cuboid = 30 m²

Total Surface area = 2 (surface area of base) + (surface area of 4 walls)

$T.S.A=2(L\times B+B\times H+\times L)T.S.A=2(L\times B)+2(B\times H+H\times L)T.S.A.=2\left(\mathrm{Surface}\mathrm{area}\mathrm{of}\mathrm{base}\right)+2H(L+B)$

50 = 2 (surface area of base) + (lateral surface area)

50 = 2 (surface area of base) + 30

50 – 30 = 2 (surface area of base)

20 = 2 (surface area of base)

Surface area of base = 20/2

= 10 m²

∴ Area of base is 10m²