Question

A cuboidal parcel is being packed in cardboard. If the parcel is 64 cm long, 8 cm wide, and 1 cm thick, what is the area of cardboard required?

• A. 200 ${\mathrm{cm}}^2$
• B. 1168 ${\mathrm{cm}}^2$
• C. 640 ${\mathrm{cm}}^2$
• D. 784 ${\mathrm{cm}}^2$

Answer 1

The correct option is B 1168 ${\mathrm{cm}}^2$

Given,
Length of parcel = 64 cm
Breadth of parcel = 8 cm
Height of parcel = 1 cm

The area of cardboard required = Total surface area (TSA) of the cuboid

TSA = $2(lb+lh+bh)$
= 2[(64 × 8) + (64 × 1) + (8 × 1)]
= 1,168 ${\mathrm{cm}}^2$

Therefore, the area of cardboard required is 1,168 ${\mathrm{cm}}^2$.