A cup of milk contains 3 parts pure milk and 1 part water. How much of the mixture must be withdrawn and water replaced in order to get the resulting mixture may be half milk and half water?

\frac{1}{3}

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\frac{1}{4}

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\frac{1}{5}

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\frac{1}{6}

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Solution

The correct option is A $\frac{1}{3}$
b'Short cut: Mixture withdrawn
$displaystyle=frac12timesfrac3−13=frac13$ '.

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A cup of milk contains 3 parts pure milk and 1 part water. How much of the mixture must be withdrawn and water replaced in order to get the resulting mixture may be half milk and half water?

The correct option is A 13b'Short cut: Mixture withdrawndisplaystyle=frac12timesfrac3−13=frac13'.

The correct option is A $\frac{1}{3}$
b'Short cut: Mixture withdrawn
$displaystyle=frac12timesfrac3−13=frac13$ '.