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A current 10 ...

Question

A current 10 ampere is maintained in a conductor of cross-section of $10^{- 4} m^{2}$ if the electron density is $9 \times 10^{28} m^{- 2}$ what is the drift velocity of free electrons?

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Solution

As we know relation between current and drift velocity
I. e I = $v_{d} e n a$
where I = current
$v_{d}$ =drift velocity
e = electron
n = no of electrons per unit volume
a =area of cross section
10= $9 \times 10^{28} \times 10^{- 4} \times v_{d}$
$v_{d}$ = $1.1 \times 10^{- 24}$

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