Question

A current carrying closed loop in the form of a right angle isosceles triangle ABC is placed in a uniform magnetic field acting along AB. If the magnetic force on the arm BC is $\overrightarrow{F}$, the force on the arm AC is:

Answer 1

Force along AB is zero as magnetic field is along AB.
The net force on a current carrying loop is always zero.
$F_{net}=F$ on $AB\to +F$ on $BC\to +F$

Hence on AC,
$⟹0=0+F+$ (F on AC)
Hence , F on AC is $-F$