You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Physics

Polarity of an Electromagnet

A current car...

Question

A current carrying coil having n-turns of cross-section area A is resting in a uniform magnetic field B. Current flowing in the coil is I and plane of coil is making an angle θ with the field. Torque acting on the coil is

Open in App

Solution

Suggest Corrections

Similar questions

Q. A coil of area

100 c m^{2}

having

500

turns carries a current of

1 m A

. It is suspended in a uniform magnetic field of induction

10^{- 3} W b / m^{2}

. It's plane makes an angle of

60^{o}

with the lines of induction. The torque acting on the coil is :

A coil of area 100 cm^2 having 500 turns carries a current of 1 m A. It is suspended in a uniform magnetic field of induction 10^-3wb/m^2. Its plane making an angle of 60° with the lines of induction. the torque acting on the coil is

Q. A square coil of N turns (with length of each side equal L) carrying current i is placed in a uniform magnetic field

\to B = B_{0}^j

as shown in figure. What is the torque acting on the coil

Q. When a current carrying coil is placed in a uniform magnetic field of induction

B

, then a torque

τ

acts on it. If

I

is the current,

n

is the number of turns and

A

is the face area of the coil and the normal to the coil makes an angle

θ

with

B

, Then

Q. A coil of area

100 {cm}^{2}

having

500

turns carries a current of

1 mA

. It is suspended in a uniform magnetic field of

10^{- 3} {wb /m}^{2}

. If the torque acting on the coil is

250 \times 10^{- 8} Nm

, then the angle made by the plane of the coil with the field is

Join BYJU'S Learning Program