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Question

A current carrying conducting square frame of side l carrying current I is placed in a uniform transverse magnetic field B as shown in the figure. Choose the incorrect statement.
1100206_8f01dbe3bcd846c7936fd784349a5c61.png

A
Magnitude of force on the frame is 4IBl
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B
Magnitude of torque on the frame Il2B
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C
Torque on the frame is zero
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D
Both (1) and (2)
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Solution

The correct option is A Magnitude of force on the frame is 4IBl
Magnetic force due to a current carrying conductor is F=BIlsinθ
Since the ring is forming a square loop where curreent flowing in each sides is same ie; I.
Therefore, Magnetic force on the frame due to magnetic field is, F=(4l)BIsin900
F=4lBI

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