Question

A current carrying loop is free to turn in a uniform magnetic field. The loop will then come into equilibrium when its plane is inclined at

• A. $0^{\circ }$ to the direction of the field
• B. ${45}^{\circ }$ to the direction of the field
• C. ${90}^{\circ }$ to the direction of the field
• D. ${135}^{\circ }$ to the direction of the field

Answer 1

The correct option is C ${90}^{\circ }$ to the direction of the field

In equilibrium angle between $\overrightarrow{M}$ and $\overrightarrow{B}$ is zero. It happens when plane of the coil is perpendicular to $\overrightarrow{B}$.