Magnetic Field Due to a Straight Current Carrying Conductor
A current-car...
Question
A current-carrying ring is placed in a magnetic field. The direction of the field is perpendicular to the plane of the ring
A
there is no net force on the ring
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B
the ring will tend to expand
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C
the ring will tend to contract
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D
either (b) or (c) depending on the directions of the current in the ring and the magnetic field
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Solution
The correct options are A there is no net force on the ring D either (b) or (c) depending on the directions of the current in the ring and the magnetic field A current-carrying ring is placed in a magnetic field and the direction of the field is perpendicular to the plane of the ring hence, there is no net force on the ring. Also if direction of current through the ring is clockwise then it will expand and will contract if direction of current through the ring is anti-clockwise.