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Question

A current carrying straight wire is kept along the axis of a circular loop carrying a current. The straight wire

A
Will exert an inward force on the circular loop
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B
Will exert an outward force on the circular loop
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C
Will exert a force on the circular loop parallel to itself
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D
Will not exert any force on the circular loop
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Solution

The correct option is B Will not exert any force on the circular loop
The figure shows that, magnetic field due to straight wire is either parallel or antiparallel to the current flow in loop depending on direction of current in wire. Thus force FF exerted by this magnetic field BB is
F = Idl × B =IdlBsinθ=0[θ=0or180]

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