A current i passes through a wire of length L, radius R and resistively ρ. The rate of heat generated is
A
iρLπr2
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B
i2(Lρπr2)
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C
(i2ρLr)
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D
noneofthese
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Solution
The correct option is Bi2(Lρπr2) A current i passes through a wire of length L, radius R and resistivity . The rate of heat generated is H=i2R ..................................................(1) The resistance of a wire is proportional to the length directly and to the area of cross section inversely i.e. R∝LA R=ρLA Also, if r is the radius of wire then A=πr2 Hence, R=Lρπr2 H=i2(Lρπr2)