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Question

A current i reaching at a point in a circuit gets branched and flows through two resistors R1 and R2. Then, the current through R1 varies as

A
R1
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B
R2
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C
(R1+R2)
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D
1/(R1+R2)
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Solution

The correct options are
B R2
D 1/(R1+R2)


Since potential difference across both resistance is same in parallel combination.
Hence i2R1=i1R2

i1=R1R2i2

Now, from Kirchoff's junction law-

I=i1+i2

R1R2i1+i1=I

i1=R2R1+R2I

i1R2
and

i11R1+R2

Answer-(B),(D)

851848_330785_ans_0097c5aca8fe483c950500f31c8f5caf.jpg

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