A current of 0.1A was passed for 2hr through a solution of cuprocyanide and 0.3745g of copper was deposited on the cathode. Calculate the current efficiency for the copper deposition ( Cu = 63.5)
Ans : 79%
Please give detailed explanation as I won't be able to understand concise answers.
Therotical is detived one
m=ZIT
Z=Molar mass/F
F=96500
m(theoretical)=63.5×0.1×7200/96500=0.4738g
∴% efficiency =0.3745/0.4738×100=79%