Question

A current of 0.5 A passes through a conductor in 2 seconds. How many electrons flow through this conductor from one end to the other end during this interval of time?

[Charge on each electron is $1.6\times {10}^{-19}C$]

• A. $6.25\times {10}^{18}$ electrons
• B. $3.15\times {10}^{19}$ electrons
• C. $1.53\times {10}^{19}$ electrons
• D. $1\times {10}^{18}$ electrons

Answer 1

The correct option is A $6.25\times {10}^{18}$ electrons

Charge flow $Q=i\times t=0.5\times 2=1$
we know that $Q=ne$ where n is no. of electrons.

So, number of electrons $n=\frac{1}{1.6\times {10}^{-19}}=$ $6.25\times {10}^{18}$ electrons.