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Question

A current of 0.5 ampere when passed through AgNO3 solution for 193 seconds deposited 0.108 g of Ag. The equivalent weight of Ag is:

A
10.8
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B
108
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C
54
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D
1
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Solution

The correct option is B 108
Given: Current ,I = 0.5 A
Time,t = 193s
Deposited Ag (W) =0.108g
Solution:
Q=It , where Q= quantity of electricity in Coloumb, I is current in amperes and time is in seconds.
Q=0.5 A× 193 s
Q=96.5C
AgNO3Ag+1+NO13
Ag+1+eAg
Therefore, Number of electrons , n=1
96.5 C of electricity deposits Ag=0.108g

96500 C of electricity deposits Ag =0.10896.5×96500
= 108g

Therefore, equivalent weight is E=108n
E= 108 g

Hence, option B is correct.

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