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Current and Drift Velocity Relation

A current of ...

Question

A current of $1.0 A$ exists in a copper wire of cross-section $1.0 m m^{2} .$ Assuming one free electron per atom calculate the drift speed of the free electrons in the wire. The density of copper is $9000 k g m^{- 3} .$

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Solution

$M o l e = (\frac{M a s s}{63.546}) = (\frac{9000}{63.546})$
$M o l e = 141.62$
$T o t a l a t o m = 141.62 \times N A = T o t a l e l e c t r o n s$
$V_{d} = (\frac{I}{n A q}) = \frac{1}{141.62 \times 6.6 \times 10^{- 1} \times 1 \times 10^{- 6} \times 1.6 \times 10^{- 19}}$
$V_{d} = \frac{100}{141.62 \times 6.6 \times 1.6} = 0.06 m / s$

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