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Byju's Answer
Standard XII
Physics
Ampere's Circuital Law
A current of ...
Question
A current of
1
A
is flowing in a coil of
10
turns having radius
10
c
m
s
. Its magnetic moment will be
A
3140
A
m
2
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B
100
A
m
2
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C
μ
0
A
m
2
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D
0.314
A
m
2
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Solution
The correct option is
C
0.314
A
m
2
A
=
π
r
2
=
3.14
×
(
10
×
10
−
2
)
2
=
3.14
×
10
−
2
N
=
10
i
=
1
A
∴
μ
=
N
i
A
=
10
×
1
×
3.14
×
10
−
2
=
0.314
A
m
2
Suggest Corrections
0
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