Question

A current of 10 A is flowing in a wire of length 1.5 m. A force of 15 N acts on it when it is placed in a uniform magnetic field of 2 T. The angle between the magnetic field and the direction of the current is:

• A. ${30}^0$
• B. ${45}^0$
• C. ${60}^0$
• D. ${90}^0$

Answer 1

Answer: (A)

${30}^0$

I=10 A

Length$L=1.5$m

Force$F=15$ N

Puting the above values in the formula below,we get

Magnetic field$=\overrightarrow{B}=2T$

$F=BIl\sin \theta \sin \theta =\frac{1}{2}\theta =30°$