The correct option is B 48.25
Given :
Mass deposited =3 g
Current, I =10 ATime, t =10 minutesTime, t =600 s
By Faraday's First law,
The mass deposited/released of any substance during electrolysis is proportional to the amount of charge passed into the electrolyte.
W∝Q
W=ZQ
where,
W: Mass deposited or liberated
Q: Amount of charge passed
Z: Electrochemical equivalent of the substance
Since,
Z=E96500
W=E96500×Q
where,
E is Equivalent weight
Charge, Q =I×t
Q=10×600
Hence,
W=Z×i×t
3=E96500×10×600
∴E=(3×9650010×600)=48.25