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Question

A current of 10 A exists in a wire of cross-sectional area 5 mm2. The drift velocity of the electrons is 2×103 m/s. The number of free electrons in each cubic meter of the wire are :

A
1×1023
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B
2×106
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C
2×1025
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D
625×1025
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Solution

The correct option is D 625×1025
Current through a wire is given by,

I=neAvd

n=IeAvd

From the given data,

n=101.6×1019×5×106×2×103

n=6.25×1027=625×1025

Hence, option (D) is the correct answer.

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