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Question

A current of 13.4A is passed through 1.0L of 1.0M HCl solution by using Pt electrodes for 1.0 hr. The pH of the solution after the experiment is over at 298K will be about.

A
0.20
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B
0.30
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C
0.40
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D
0.50
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Solution

The correct option is B 0.30
(B)0.30
Change in coulombs =13.4×1×60×60=48240

Moles of electric charge =4824096500=0.5F

Equivalent of HCl decomposed on electrolysis =0.5

Mili equivalents of HCl along electrolysis =500

Molarity of HCl after electrolysis =5001000=0.5M

[H+]=5×101

pH=log[H+]

pH=log5×101=0.30.

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