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Question

A current of 2 A flows in a system of conductors as shown. The potential difference (VAVB) will be

A
+ 2V
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B
+ 1V
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C
– 1 V
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D
– 2 V
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Solution

The correct option is B + 1V
In the given circuit 2A current divides equally at junction D along the paths DAC and DBC (each path carry 1A current).
Potential difference between D and A, VDVA=1×2=2 volt .......(i)
Potential difference between D and B, VDVB=1×3=3 volt .......(ii)
On solving (i) and (ii) VAVB=+1 volt

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