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Equivalent Resistance in Series Circuit

A current of ...

Question

A current of $2$ A flows in an electric circuit as shown in figure. The potential difference $(V_{R} - V_{S})$ , in volt $(V_{R}$ and $V_{S}$ are potentials at R and S respectively $)$ is?

A

- 4

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B

+ 2

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C

+ 4

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D

- 2

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Solution

The correct option is C $+ 4$
Resistance of PRQ $= 10 Ω$ .
Resistance of PSQ $= 10 Ω$ .
$∴$ Current at P divides equally along PRQ and PSQ.
$∴$ Current along PRQ $= 1$ A and current along PSQ $= 1$ A.
$(V_{P} - V_{R}) = ($ Current $1) \times ($ resistance $3) = 3$ volt ........(i)
$(V_{P} - V_{S}) = 1 \times 7 = 7$ volt ........(ii)
Now subtract (i) from (ii)
$(V_{P} - V_{S}) - (V_{P} - V_{R}) = 7 - 3$ , or $V_{R} - V_{S} = + 4$ volt.

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