a current of 2 ampere is flowing through a coil of radius 0 1m andnhaving 10 turns the magnetic moment of the coil will be

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Solution

Magnetic moment of the coil = NIA = (10)(2)(Ï€(0.1)²)
= 0.628

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a current of 2 ampere is flowing through a coil of radius 0 1m andnhaving 10 turns the magnetic moment of the coil will be

Magnetic moment of the coil = NIA = (10)(2)(Ï€(0.1)2) = 0.628

Magnetic moment of the coil = NIA = (10)(2)(Ï€(0.1)²)
= 0.628