A current of 200 mA flows through a 4 k - resistor- What is the p-d- across the resistor-

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Physics

Ohm's Law

A current of ...

Question

A current of 200 mA flows through a 4 kΩ resistor. What is the p.d. across the resistor?

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Solution

A current of 200 mA flows through a 4 kΩ resistor.
So current, I = 200 mA = 200 x 10^-3A
Resistance, R = 4 kΩ = 4000 Ω
Potential difference, V = IR
V = 200 x 10^-3x 4000
V = 800 V
So the potential difference across the resistor will be 800 V.

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A current of 200 mA flows through a 4 kΩ resistor. What is the p.d. across the resistor?

A current of 200 mA flows through a 4 kΩ resistor. So current, I = 200 mA = 200 x 10-3A Resistance, R = 4 kΩ = 4000 Ω Potential difference, V = IR V = 200 x 10-3 x 4000 V = 800 V So the potential difference across the resistor will be 800 V.

A current of 200 mA flows through a 4 kΩ resistor.
So current, I = 200 mA = 200 x 10^-3A
Resistance, R = 4 kΩ = 4000 Ω
Potential difference, V = IR
V = 200 x 10^-3x 4000
V = 800 V
So the potential difference across the resistor will be 800 V.