The correct option is C 1.5×1022
A current of 2A passes through a wire for 20 minutes. The number of electrons that crossed the cross-section in this period is
Given
Current through the wire is I=2A
Time for which current flows through the wire is t=20min=20×60s
Let n and e be the number and charge of electrons that crossed the cross-section of wire in time t.
Now, the total charge, q(say) in the wire is
q=ne
Hence, the current flowing in time t is
I=qt
I=net
∴n=Ite
∴n=(2)(20×60)1.6×10−19
∴n=24001.6×10−19
∴n=1500×1019
∴n=1.5×1022