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Conductance and Conductivity

A current of ...

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A current of 2A was passed for 1.5 hours through a solution of CuSO_4 when 1.6 g of copper was deposited. Calculate percentage current efficiency

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Q. A current of 0.1A was passed for 4hr through a solution of cuprocyanide and 0.3745 g of copper was deposited on the cathode. Calculate the current efficiency for the copper deposition:

Q. A current of

0.1 A

2

hr through a solution of cupro cyanide and

0.3745

g of copper was deposited on the cathode.

Calculate the current efficiency for the copper deposition.

C u = 63.5

Q. Calculate the time to deposit

1.27 g

of copper at, cathode when a current of

2 A

was passed through the solution of

C u S O_{4}

. (Molar mass of

C u = 63.5 g m o l^{- 1}, 1 F = 96500 C m o l^{- 1}

)

Q. A current of

2.6 a m p

was passed through

C u S O_{4}

6

20

seconds. The amount of copper deposited is:

Q. Through a solution of

C u S O_{4}

3

amperes was passed for

2

hours. At cathode,

3 g

C u^{2 +} i o n s

were discharged. The current efficiency is : [At. wt. of

C u = 63.5

]

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