Question

A current of $3.2A$ is flowing through a conductor. The number of electrons flowing per second is

• A. $51.2\times {10}^{19}$
• B. $5.12\times {10}^{24}$
• C. $3.2\times {10}^{19}$
• D. $2\times {10}^{19}$

Answer 1

The correct option is D

$2\times {10}^{19}$

Step 1: Analyzing the given data:

Given:

Current flowing through the conductor $\left(I\right)=3.2A$

Find:

Number of electrons flowing per second $\left(n\right)$

Step 2: Calculating the number of electrons flowing per second:

We know that:

$I=ne$

$\therefore n=\frac{I}{e}$

where $e$ is the fundamental value of charge,

$\therefore n=\frac{3.2}{1.6\times {10}^{-19}}$

$\therefore n=2\times {10}^{19}$

Hence, option (D) is the correct answer.