A current of 3 A is flowing in a linear conductor having a length of 40 cm. The conductor is placed in a magnetic field of strength 500 gauss and makes an angle 30o with the direction of the field. It experiences a force of magnitude
A
3×10−4N
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B
3×10−2N
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C
3×102N
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D
3×104N
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Solution
The correct option is B3×10−2N F=ILBsinθ =3×0.40×(500×10−4)×sin30o =3×10−2N