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Symmetry in Circuits

A current of ...

Question

A current of 3A flows in a circuit shown in the figure. The potential difference between A and B is

A

4V

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B

3V

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C

2V

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D

1V

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Solution

The correct option is C 2V

$3 = i_{1} + i_{2} \to 1 i_{2} = 3 - i_{1} - 4 i_{1} - 6 i_{1} + 5 (3 - i_{1}) = 0 15 - 5 i_{1} = 10 i_{1} 15 = 15 i_{1} i_{1} = 1 A i_{2} = 2 A V_{A} - 6 \times + 2 \times 2 = V_{B} V_{A} - V_{B} = 6 - 4 = 2 V$

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