Question

A current of $4.8A$ is following in a conductor. The number of electrons passing per sec through the conductor will be:

• A. $3\times {10}^{20}$
• B. $76.8\times {10}^{20}$
• C. $7.68\times {10}^{-19}$
• D. $3\times {10}^{19}$

Answer 1

The correct option is D $3\times {10}^{19}$

We know that current is $i=\frac{Q}{T}$ also time t=1 sec , i=4.8A

let the total number of electron be n , then $Q=ne$ , e is charge of electron

So $i=4.8=\frac{ne}{t}=\frac{n\times 1.6\times {10}^{-19}}{1}$

$n=3\times {10}^{19}$