Question

A current of $4A$ is passed through a straight wire of length $3cm$ in a uniform perpendicular magnetic field of $12T$. What is the magnetic force experienced by the wire?

Answer 1

Step 1. Given data

The length of the wire is, $L=3cm=0.03m$

Current is, $I=4A$

The intensity of the magnetic field is, $B=12T$.

Step 2. Formula used

Force on a straight current-carrying conductor placed in a uniform perpendicular magnetic field, $F=B\times L\times I$

Where, $B$ is the magnetic field, $L$ is the length of the wire, $I$ is the current.

Step 3. Finding magnetic force

$F=BLI$

Put all the values in formula,

$F=12T\times 0.03m\times 4A$

After solving we get,

$F=1.44N$

Therefore, the magnetic force experienced by the wire is $\mathbf{1}\mathbf{.}\mathbf{44}\mathbf{}\mathit{N}$.