A current of 5.0 A exists in the circuit shown in figure (34 - E3). The wire PQ has a length of 50 cm and the magnetic field in which it is immersed has a magnitude of 0.20 T. Find the magnetic force acting on the wire PQ.

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Solution

Magnetic force on wire PQ

$= i l B s i n 90^{o}$

$= 5 \times 50 \times 10^{- 2} \times 0.2 \times 1$

$= 0.50$ N towards inside the circuit,

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A current of 5.0 A exists in the circuit shown in figure (34 - E3). The wire PQ has a length of 50 cm and the magnetic field in which it is immersed has a magnitude of 0.20 T. Find the magnetic force acting on the wire PQ.

Magnetic force on wire PQ =ilB sin 90o =5×50×10−2×0.2×1 =0.50N towards inside the circuit,

Magnetic force on wire PQ

$= i l B s i n 90^{o}$

$= 5 \times 50 \times 10^{- 2} \times 0.2 \times 1$

$= 0.50$ N towards inside the circuit,