Question

A current of $7A$ flows through the circuit as shown in the figure. The potential difference a across point B and $C$ is

• A. $6V$
• B. $8V$
• C. $4V$
• D. $10V$

Answer 1

The correct option is D $10V$

$10V$

current flowing through the upper wire $=7\times \left[\frac{15}{6+15}\right]=5A$

Now, Current through the Series is same, So $I=5A$, for both $4\Omega$ and $2\Omega$

Potential different across $2\Omega$ resistor (i.e., potential difference across BC)

$=2\times 5=10V$