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Molarity

A current of ...

Question

A current of $965 A$ is passed for $100$ sec between inert electrodes in $500 m L$ solution of $2 M$ $C u {S O}_{4}$ . The molarity of solution after electrolysis would be:
(Assume no change in volume)

2 M

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1 M

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4 M

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0.5 M

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Solution

The correct option is B $1 M$
Moles of $C u$ deposited be $n$
$∵ W = Z i t$
$∵ n = \frac{i t}{96500 \times 2}$ $[E q u i v a l e n t W e i g h t = \frac{A t o m i c w e i g h t}{n - f a c t o r}]$
$∴ n = \frac{965 \times 100}{96500 \times 2} = 0.5$
Initial moles= $500 \times 10^{- 3} \times 2 = 1$
$∴$ Moles of $C u$ left= $1 - 0.5 = 0.5$
$∴$ Molarity after electrolysis= $\frac{0.5}{500 \times 10^{3}} = 1 M$

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