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Relationship between Vapor Density & Relative Molecular Mass

A current of ...

Question

A current of dry air was bubbled through bulb containing 26.66 g of an organic compound in 200 g water, then through a bulb at the same temperature, contains water and finally through a tube containing anhydrous calcium chloride. The loss of mass in bulb containing water was 0.089 and gain in mass of the calcium chloride tube was 2.036. Calculate the molecular mass of the organic substance.

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Solution

$\frac{P_{0} - P_{s}}{P_{0}} = \frac{L o s s i n m a s s o f s o l v e n t b u l b}{G a i n i n m a s s o f C a C l_{2} t u b e}$
$= \frac{0.087}{2.036}$
Let the molecular mass of the organic substance be m.
According to Raoult's law,
$\frac{P_{0} - P_{s}}{P_{0}} = \frac{w / m}{\frac{w}{m} + \frac{W}{M}}$
$\frac{0.087}{2.036} = \frac{\frac{26.66}{m}}{\frac{26.66}{m} + \frac{200}{18}} = \frac{26.66}{26.66 + \frac{200}{18} m}$
$m = 53.75$

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