A current of 14π amp is flowing in a long straight conductor. The line integral of magnetic induction around a closed path enclosing the current carrying conductor is
A
10−7wb/m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
4π×10−7wb/m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
16π2×10−7wb/m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Zero
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A10−7wb/m ∮Bdl=μ0i=4π×10−7×14π=10−7wb/m