Question

A current of two amperes is flowing through a cell of e.m.f. 5 volts and internal resistance 0.5 ohm from negative to positive electrode. If the potential of negative electrode is 10V, the potential of positive electrode will be

• A. 5 V
• B. 14 V
• C. 15 V
• D. 16 V

Answer 1

The correct option is B 14 V

$V_2-V_1=E-ir=5-2\times 0.5=4$ volt
$\Rightarrow V_2=4+V_1=4+10=14$ volt