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Question

A current sheet

J=10^uyA/m lies on the dielectric interface x = 0 between two dielectric media with

εr1=1,μr1=1 in Region -1 (x < 0) and εr2=2,μr2=2 in Region-2 (x > 0). If the magneitc field in Region-1 at x = 0+ is H1=3^ux+30^uyA/m, the magnetic field in Region-2 at x=0+ is


A
H2=1.5^ux+30^uy10^uzA/m
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B
H2=3^ux+30^uy10^uzA/m
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C
H2=1.5^ux+40^uyA/m
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D
H2=3^ux+30^uy+10^uzA/m
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Solution

The correct option is A H2=1.5^ux+30^uy10^uzA/m
Ans : (a)

For magnetic field boundary relations are

Bn1=Bn2
andHt1Ht2=Js×an
Bx1=Bx2 (x is normal component)
μ1Hx1=μ2Hx2
1×3=2×Hx2
Hx2=1.5
Ht1Ht2=10^uy×^ux=+10^uz
Ht2=Ht110^uz
Ht2=30^uy10^uz
H2=1.5^ux+30^uy10^uzA/m


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