You visited us 1 times! Enjoying our articles? Unlock Full Access!

Stationary Point

A curve has e...

Question

A curve has equation $(x - 4)^{2} + (y + 1)^{2} = 36$ . If the origin is translated to $(4, - 1)$ , then the equation of the curve in translated system becomes $X^{2} + Y^{2} = K^{2}$ . Find the value of $K$ .

Open in App

Solution

Given the curve has equation $(x - 4)^{2} + (y + 1)^{2} = 36$
$∴$ The center = (4,-1) and radius=6
The orgin is transfered to (4,-1) i.e, to the centervof curve
$x^{2} = (x - 4)^{2}, y^{2} (y + 1)^{2} ∴ K^{2} = 36 ⟹ k = 6$

Suggest Corrections

Similar questions

(y + 2)^{2} = 8 (x - 3)

(3, - 2)

Y^{2} = K X

K

x^{2} - 4 | x | - 12 = 0

x - y

y = k

k

P (5, 5)

x^{2} + y^{2} - 4 x - 6 y - 12 = 0

x^{2} + y^{2} = 25

P =

y \frac{d y}{d x} = \pm \sqrt{k^{2} - y^{2}}

x y - 2 x - 3 y - 4 = 0

X Y = k

k =

Join BYJU'S Learning Program