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Stationary Point

A curve has t...

Question

A curve has the equation $(y + 2)^{2} = 8 (x - 3)$ . If the origin is translated to $(3, - 2)$ , then the equation of the curve in the translated system becomes $Y^{2} = K X$ . Find the value of $K$ .

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Solution

Given the equation , $(y + 2)^{2} = 8 (x - 3)$
which is of the form $y^{2} = k x$
where the center $= (0, - 2)$ and value of $K = 8$

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