A curve is passing through the point (3, 4). At any point on that curve, its slope is equal to the reciprocal of twice the ordinate of that point. Then
A
Equation of the curve is x2=y+5
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B
Equation of the curve is y2=x+13
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C
Vertex of the curve is (-13,0)
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D
Vertex of the curve is (0,-5)
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Solution
The correct options are B Equation of the curve is y2=x+13 C Vertex of the curve is (-13,0) dydx=12y⇒2ydy=dx ⇒y2=x+c It P.T (3, 4) ⇒ c=13 ∴ eqn of curve is y2=x+13, Which is a parabola, vertex is (-13, 0)