A road is 10 m wide. Its radius of curvature is 50 m. The outer edge is above the lower edge by a distance of 1.5 m. This road is most suited for the velocity

Q. A curve in a road forms an arc of radius

800 m

If the road is

39.2 m

wide, calculate the safe speed for turning, if the outer edge of the road is

0.5 m

higher than the inner edge. Take

g = 9.8 {m/s}^{2}

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A curved road is 7.5 m wide and its outer edge is raised by 1.5 m over the inner edge. The radius of curvature is 50 m. For what speed of the car is this road suited?(g=10m/s2):

The correct option is B 10 m/sNsinθ=mv2RNcosθ=mgtanθ=v2rgtanθ=1.57.515=v250×10U=10 m/s

A curved road is $7.5 m$ wide and its outer edge is raised by $1.5 m$ over the inner edge. The radius of curvature is $50 m$ . For what speed of the car is this road suited? $(g = 10 m / s^{2})$ :

The correct option is B $10 m / s$
$N s i n θ = \frac{m v^{2}}{R}$

$N c o s θ = m g$

$t a n θ = \frac{v^{2}}{r g}$

$t a n θ = \frac{1.5}{7.5}$

$\frac{1}{5} = \frac{v^{2}}{50 \times 10}$
$U = 10 m / s$