(a) CuSO4 reacts with
KI in acidic medium to liberate
I2.
2CuSO4+4KI⟶Cu2I2+2K2SO4+I2(b) Mercuric perisdate,
Hg5(IO6)2 reacts with a mixture of
KI and
HCl according to the following the equation:
Hg5(IO6)2+34KI+24HCl⟶5K2HgI4+8I2+24KCl+12H2O(c) The liberated iodine is titrated against
Na2S2O3 solution, one mL of which is equivalent to
0.0499 g of
CuSO4.5H2O.
What volume in mL of Na2S2O3 solution will be required to react with I2 liberated from 0.7245 g of Hg5(IO6)2? (Molar mass of CuSO4.5H2O=249.5 g/mol and of Hg5(IO6)2=1448.5 g/mol)