Question

A customer orders $2lb$ of cheese from a store. The store worker places some cheese in a bowl and weighs it. The scale shows $1\frac{1}{4}lb$. The weight of the bowl is $\frac{1}{8}lb$. How much cheese needs to be added to the bowl?

• A. $\frac{7}{8}lb$
• B. $\frac{15}{8}lb$
• C. $\frac{5}{4}lb$
• D. $\frac{1}{8}lb$

Answer 1

The correct option is A $\frac{7}{8}lb$

Detailed step-by-step solution:
Total quantity of cheese ordered by the customer $=2lb$
Weight of the bowl $=\frac{1}{8}lb$
Total weight of the cheese and the bowl $1=\frac{1}{4}lb$
The actual weight of the cheese in the bowl $1=\frac{1}{4}lb-\frac{1}{8}lb$
$1\frac{1}{4}lb-\frac{1}{8}lb=\frac{1\times 4+1}{4}lb-\frac{1}{8}lb=\frac{5}{4}lb-\frac{1}{8}lb=\frac{5\times 2}{4\times 2}lb=\frac{10}{8}lb-\frac{1}{8}lb=\frac{10-1}{8}lb=\frac{10-1}{8}lb=\frac{9}{8}lb$
Quantity of cheese that needs to be added $=2lb-\frac{9}{8}lb=\frac{2\times 8}{1\times 8}lb-\frac{9}{8}lb=\frac{16}{8}lb-\frac{9}{8}lb=\frac{16-9}{8}=\frac{7}{8}lb$
Hence, option C is correct.