wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A cycle is going on an overbridge of radius R. The driver maintains a constant speed. As the cycle is ascending on the overbridge, the normal force on it:

A
increases
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
decreases
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
remains the same
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
fluctuates
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A increases

As we know that, normal force will pass through the centre of the bridge., and net force towards the centre of overbridge is

Fcentre=mgcosθN (From FBD)

And here, Fcentre is the responsible for the circular motion. So

mgcosθN=mv2R

N=mgcosθmv2R

Since, m, R,g and speed v are constant.

N increases with cosθ

When ascending, θ will decrease, so cosθ will increase means normal force increases.
Why this question ?
Tip: In this question, we can observe how normal force changes in vertical circular motion.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Kinetic Energy and Work Energy Theorem
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon