A cycle shown in the figure is composed of internally reversible processes. What is the thermal efficiency of following cycle?

0.25

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0.33

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0.5

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0.75

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Solution

The correct option is A 0.25
Given, $T_{1} = 400 K$

$T_{2} = T_{3} = 800 K$

Now, $η = \frac{N e t w o r k}{H e a t s u p p l i e d} = \frac{a r e a 1 - 2 - 3 - 1}{a r e a a - b - 3 - 2 - a}$

$∴$ $η = \frac{\frac{1}{2} (T_{3} - T_{1}) (S_{b} - S_{a})}{(S_{b} - S_{a}) (T_{3})} = \frac{T_{3} - T_{1}}{2 T_{3}} = \frac{800 - 400}{2 \times 800} = 0.25$

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