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Question

A cyclic process for 1 mole of an ideal gas is shown in figure in the VT diagram. The work done in process AB,BC and CA respectively, are



A
0,2RT2ln(V1V2),R(T1T2)
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B
R(T1T2),0,RT1lnV1V2
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C
0,RT2ln(V2V1),2R(T1T2)
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D
0,RT2ln(V2V1),R(T2T1)
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Solution

The correct option is D 0,RT2ln(V2V1),R(T2T1)
From the VT graph,

In process AB, volume is constant.
As volume is constant, work done in this process is 0.

In process BC, temperature is constant.
Work done in isothermal process is
WBC=RT2ln(V2V1)

In process CA, VT 
or VT is constant i.e pressure is constant.
[from PV=nRT]
WCA=PΔV=R(T1T2)=R(T2T1)
Thus, option (d) has the correct graph.

Physics

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