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Standard XII
Physics
Thermodynamic Processes
A cyclic proc...
Question
A cyclic process is shown in the figure.Work done during isobaric expansion is:
A
1600 J
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B
100 J
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C
400 J
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D
600 J
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Solution
The correct option is
C
400 J
We know AB is the isobaric process ass it has constant pressure. And work done is equal to area under AB.
i.e.,
Work Done=area under AB=
P
Δ
V
=
2
×
10
2
×
(
3
−
1
)
=
200
×
2
=
400
J
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