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Question

A cyclic process is shown in the figure.Work done during isobaric expansion is:
582720_5c47f814058d4adbb6403a9a4d54f477.png

A
1600 J
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B
100 J
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C
400 J
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D
600 J
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Solution

The correct option is C 400 J
We know AB is the isobaric process ass it has constant pressure. And work done is equal to area under AB. i.e.,
Work Done=area under AB=PΔV=2×102×(31)=200×2=400J

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